If the side of a cube is increased by 12% by how much percent does it volume increase?
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Hol@ mate!!! Here is ur ans :
Here,
x = 12% According to the formula, Percentage increase in volume = [(1+x100)3−1]×100%
[(1+x100)3−1]×100%=[(1+12100)3−1]×100%
[(1+x100)3−1]×100%=[(1+12100)3−1]×100%= [(1.12)3−1]×100%
[(1+x100)3−1]×100%=[(1+12100)3−1]×100%= [(1.12)3−1]×100%=0.404928×100% = 40.4928%
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