if the side of a rectangle are in the ratio 9:5 and it's perimeter is 42 cm , find its area
Answers
Answered by
1
Answer:
101.25cm^2
Step-by-step explanation:
Let the common factor be x.
Thus the sides of the rectangle are 9x and 5x.
Perimeter of rectangle- 2(l+b)
P=2(9x+5x)
We know the perimeter is 42cm.
42=2(14x)
42=28x
x=1.5
Thus the sides are
(9×1.5) And (5×1.5)
13.5 and 7.5
Area= 13.5×7.5 (length×breadth)
Area=101.25cm^2
Answered by
0
Step-by-step explanation:
Let length =9x
breadth=5x
Perimeter of rectangle=2 (l+b)
42 cm =2 (9x+5x)
42÷2 = 14x
21 =14x
21÷14 =x
1.5cm =x
Length = 9×1.5=13.5cm
Breadth =5×1.5=7.5cm
Area of rectangle =length×breadth
=(13.5×7.5)cm
=101.25cm square
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