Question

if the side of a rhombus is 10 cm and one digonal 16 cm then find the area​

Answer 1

Let ABCD is a rhombus

AC=16 AB=10

O is the point where digonal intersect each other

in right angle triangle

using pytagoras theorem

AB^2= AO^2+ BO^2

10^2=8^2+ BO^2

BO=6

area = 1/2× product of diagnoals

=1/2×16×12

=96 CM^2

I hope this will help you a lot

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