Question

If the side of a rhombus is 10 cm and one of its diagonal 16 cm, then using the pythagoras theorem find its area.​

Answer 1

Answer:

Step-by-step explanation:

16(diagonal)÷2...(side of right triangle) There are 4 right triangles...

By using Pythagoras theorem,

8^2+x^2=10^2 (where x= 3rd side)

64+x^2=100

100-64=x^2

36=x^2

6^2=x^2

6=x

Therefore,

1/2×b×h=1/2×8×6

=4×6

=24cm^2

There are 4 such triangles...

4×24= 96cm^2

Ans.96cm^2

Hope it helps..

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