Question

if the side of a square are length by 3 cm the area becomes 121 CM square find the perimeter of the original square​

Answer 1

Here, let the length of the side be x

When length is increased by 3 cm then side would be x+3

Then, area of a square = a^2

Here it would be (x+3)^2 = 121

x^2 + 3^2 + 2×x×3 = 121 {apply (a+b) ^2 = a^2 + b^2 + 2ab}

Then it would be x^2 + 9 + 6x = 121

x^2 + 6x = 121 - 9

x^2 + 6x = 112

Now by completing square method:

x^2 + 2 × 3x = 112

x^2 + 2 × 3x + 3^2 = 112 + 3^2

(x+3)^2 = 112 + 9

(x+3)^2 = 121

(x+3) = under root of 121

(x+3) = + 11

+ve -ve

x = +11 -3 x = -11 -3

x = 8 x = -14 (skip)

Here we got the side of the original square = 8cm

Now for the perimeter of the square the formula is = 4a {a = measurement of one side}

So, 4 × 8 = 32

Hence the perimeter of the original square is 32 cm.

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Answer 2

Answer:

this is the answer hope it helps you this is the step by step work