Question

If the side of a square is 1/2(x+1) unit and Its diagonal is 3-x/root 2 find the length of a side of the square

Answer 1

Answer:

hope you got your answer

Answer 2

The side length of the square is 1 unit.

Step-by-step explanation:

Let a be the side length and d is the diagonal of the square.

It has been given that

$a=\frac{1}{2}(x+1)$

$d=\frac{3-x}{\sqrt2}$

The relation between side length and diagonal of a square is given by

$d=\sqrt2 a$

Substituting the value of a and d

$\frac{3-x}{\sqrt2}=\sqrt2 \times\frac{1}{2}(x+1)$

Solve the equation for x

$3-x=x+1\\\\2x=2\\\\x=1$

Thus, the length of the square is given by

$a=\frac{1}{2}(x+1)\\\\a=\frac{1}{2}(1+1)\\\\a=\frac{1}{2}\times2\\\\a=1$

The side length of the square is 1 unit.

#Learn More:

The perimeter of a rhombus is 56 cm and height is 5 cm find its area ?​

https://brainly.in/question/11601710