Question

If the side of a square is decreased by 20% then the area is decreased by

Answer 1

Given: As per given in the question Side of a square is decreased by 20%.

To Find: We are said to find area is decresed by

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$\large{\bold{\underline{According\:to\:the\:question}}}$

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Let's consider the side of a square be 10m.

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$\large{\mathfrak{\underline{Using\:Formula}}}$

$\: \: \: \\ \: \: \sf \: area \: of \: rectangle = length \times breath$

$\large{\mathfrak{\underline{Subsitute\:the\:values}}}$

$\: \: \: \\ \: \: \sf \implies \: area \: of \: rectangle = 10 \times 10 \\ \\ \: \: \sf = 100 {m}^{2}$

• side of a square is decreased by 20% and we are said to find the area is decreased by.

$\: \: \sf \: decreased \: length \: of \: side = 10 - \frac{20 \times 10}{100} = 8m$

$\: \: \sf \: area \: = 8 \times 8 = 64 {m}^{2}$

$\: \: \sf \: decrease \: in \: area \: = 100 - 64 \\ \\ \: \: \sf \: = 36 {m}^{2}$

$\: \: \sf \: decrease \: percent = \frac{36}{1 \cancel0 \cancel0} \times 1 \cancel0 \cancel0 \\ \\ \: \: \sf \: = 36 \: percent$

$\therefore$ % decrease = 36%.