If the side of a square is doubled, how much does the perimeter of the square increase?
Please answer with explanation.
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As we know all side of square are in equal length, let say it : a.
thus perimeter of original square would be : a+a+a+a(i.e sum of length of all four side)=4*a(or four times of a).
Now ,lets turn to your question. If it’s side gets double; then all of it’s side would be double(since square has all side of equal length). then new length of side would be:
a+a=2*a(or two times of original length) .
then lets find out perimeter ,i.e sum of all four side as
(2*a)+(2*a)+(2*a)+(2*a)=8*a(eight times of a).
now change in Perimeter:(new perimeter )/(original perimeter)=(8*a)/(4*a)=2.
Hence we can conclude that If the side of square is doubled ,its perimeter would also be doubled.
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