If the side of a square is increased by 20%, its area is increased by
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0
Answer:
44%
Step-by-step explanation:
Area of square = a^2
side of square increased by 20% i.e 1.2 from 1
area= 1.2*1.2 = 1.44
area has become 1.44 from 1
therefore area has increased by 44%
Answered by
1
Step-by-step explanation:
Let the side of the square be 'x'.
We know that Area = x^2.
Given that side of a square is increased by 20%.
=> Length of each side = x + 20% of x = 120x/100 = (6/5)x
New area = (6x/5)^2 = (36x^2/25)
Now,
Increase in area = (36x^2/25) - x^2
= (36x^2 - 25x^2)/25
= 11x^2/25
So, the % increase in area = (11x^2/25) * (100/x^2)
= > 1100/25
= > 44.
Therefore, Area is increased by 44%.
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