Math, asked by meenakshimagar4337, 1 year ago

If the side of a square is increased by 20%, its area is increased by

Answers

Answered by swethasurendramalya
0

Answer:

44%

Step-by-step explanation:

Area of square = a^2

side of square increased by 20% i.e 1.2 from 1

area= 1.2*1.2 = 1.44

area has become 1.44 from 1

therefore area has increased by 44%

Answered by Salmonpanna2022
1

Step-by-step explanation:

Let the side of the square be 'x'.

We know that Area = x^2.

Given that side of a square is increased by 20%.

=> Length of each side = x + 20% of x = 120x/100 = (6/5)x

New area = (6x/5)^2 = (36x^2/25)

Now,

Increase in area = (36x^2/25) - x^2

                           = (36x^2 - 25x^2)/25

                           = 11x^2/25

So, the % increase in area = (11x^2/25) * (100/x^2)

= > 1100/25

= > 44.

Therefore, Area is increased by 44%.

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