Math, asked by poornimaaece, 11 months ago

if the side of a square is increased by 4 cm,the area increases by 60 sq.cm . the side of the square before increasing is?

Answers

Answered by chopraneetu

let the side of the square be x cm
area=side×side=x×x
on increasing
new side=x+4
new area=(x+4)(x+4)
ATQ
${(x + 4)}^{2} = {x}^{2} + 60 \\ {x}^{2} + 8x + 16 = {x}^{2} + 60 \\ 8x + 16 = 60 \\ 8x = 60 - 16 \\ 8x = 44 \\ x = \frac{44}{8} = \frac{11}{2} = 5.5 \\$
side of the square=5.5 cm

poornimaaece: i have one doubt ,how u put x^2 + 60

chopraneetu: since the new area is increased by 60

chopraneetu: that means if we add 60 to old area we will get new area

poornimaaece: ok ok i got it,thank you

chopraneetu: mark as brainliest if it helped

poornimaaece: ok

chopraneetu: thanx for marking

Answered by shivamtiwari98809880

Step-by-step explanation:

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