Question

if the side of a square is increased by 4 cm,the area increases by 60 sq.cm . the side of the square before increasing is?

Answer 1

let the side of the square be x cm
area=side×side=x×x
on increasing
new side=x+4
new area=(x+4)(x+4)
ATQ
${(x + 4)}^{2} = {x}^{2} + 60 \\ {x}^{2} + 8x + 16 = {x}^{2} + 60 \\ 8x + 16 = 60 \\ 8x = 60 - 16 \\ 8x = 44 \\ x = \frac{44}{8} = \frac{11}{2} = 5.5$
side of the square=5.5 cm

Answer 2

Step-by-step explanation:

please follow me and mark these as brainlist