If the side of a square is increased by 45% by what percent would its area increase?
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solution:-
Let the side of square be 100 unit
so area =( 100×100 )
=10000 unit^2
when side is decreased by 45℅
side =100-45℅×100
=100-45/100×100
=100-45
=55 unit
Now.
Area =(55×55)unit^2
=3025 unit^2
Decrease in area =(10000-3025) unit^2
=6975 unit^2
℅ decrease in area =(6975/10000×100)℅
=69.75℅
Hope it helped !!!!
Let the side of square be 100 unit
so area =( 100×100 )
=10000 unit^2
when side is decreased by 45℅
side =100-45℅×100
=100-45/100×100
=100-45
=55 unit
Now.
Area =(55×55)unit^2
=3025 unit^2
Decrease in area =(10000-3025) unit^2
=6975 unit^2
℅ decrease in area =(6975/10000×100)℅
=69.75℅
Hope it helped !!!!
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