Question

if the side of a square is increased by 8cm, the area increases by 64 cm2. what is the side of the square?

Answer 1

$\bold{ \underline{Let \: the \: side \: o f \: the \: Square \: is \: ( x - 8 ) \: cm , }}$



Area of square will be = side² = ( x - 8 )^2 = x^2 + 64 - 16x cm^2





$\bold{ \underline{When, \: side \: is \: increases \: by \: 8 \: cm }}$


side = ( x - 8 + 8 ) cm = x cm

Area = x² cm^2








$\mathbf{ \underline{Given \: that \: when \: side \: is \: increased \: by \: 8 cm, \: area \: increases \: by \: \: 64 cm^2 , }}$


Then, comparing areas,



⏩ x^2 = x^2 + 64 - 16x + 64

⏩ 0 = 64 + 64 - 16x

⏩ 16 x = 128

⏩ $x = \frac{128}{16}$

▶ x = 8






Hence, side of square is ( x - 8 ) = ( 8 - 8 ) cm = 0 cm




Please check your question.

Answer 2

Refer to the above attachment !!