If the side of a
triangle are in the ratio 8:4:6 and its perimeter is 72cm find the area of the triangle
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let
a=8x
b=4x
c=6x
Perimeter of triangle = 72
8x+4x+6x. =72
18x. =72
x. =72/18
x= 4
a=8x=8×4=32
b= 4x=4×4=16
c=6x=6×4=24
s=a+b+c/2
s=32+16+24/2
s=72/2
s= 36
ar∆=√s(s-a)(s-b)(s-c)
=√36(36-32)(36-16)(36-24)
=√36×4×20×12
=√2×2×3×3×2×2×2×10×2×3
= 2×2×2×3√3×10
= 24√30
area of triangle is 24√30cm sq
PLEASE MARK IT AS BRAINLIEST......
a=8x
b=4x
c=6x
Perimeter of triangle = 72
8x+4x+6x. =72
18x. =72
x. =72/18
x= 4
a=8x=8×4=32
b= 4x=4×4=16
c=6x=6×4=24
s=a+b+c/2
s=32+16+24/2
s=72/2
s= 36
ar∆=√s(s-a)(s-b)(s-c)
=√36(36-32)(36-16)(36-24)
=√36×4×20×12
=√2×2×3×3×2×2×2×10×2×3
= 2×2×2×3√3×10
= 24√30
area of triangle is 24√30cm sq
PLEASE MARK IT AS BRAINLIEST......
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