if the side of a triangle is produced in order prove that the sum of the exterior angles so formed is 360
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Suppose you have a ∆ABC
All the exterior angles will be equal to
(180-A)°
(180-B)°
(180-C)°
respectively (Angles on the same line) so if you sum it up it will be equal to 540 - (A+ B + C )
And by angle sum property A+B+C = 180°
Therefore Sum = 540 - 180 = 360
All the exterior angles will be equal to
(180-A)°
(180-B)°
(180-C)°
respectively (Angles on the same line) so if you sum it up it will be equal to 540 - (A+ B + C )
And by angle sum property A+B+C = 180°
Therefore Sum = 540 - 180 = 360
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