Question

If the side of a triangle is x x + 1 x 2 x + 1 how can we find its area

Answer 1

Answer:

Sides of triangle are x, x+1, 2x-1

Area of triangle is x \sqrt{10}

To find out:- Value of x

We Know That,

Semi-Perimeter(S)= Perimeter/2

=x+x+1+2x-1/2

=4x/2

=2x

Area Of Triangle= \sqrt{s(s-a)(s-b)(s-c)}

or, x \sqrt{10} = \sqrt{2x(2x-x)(2x-x-1)(2x-2x+1)}

or, x \sqrt{10} =[tex] \sqrt{2x.x(x-1).1}

or, x \sqrt{10} =[tex] \sqrt{2x^2(x-1)}

or, x \sqrt{10} =<strong></strong>[tex]x\sqrt{2(x-1)}

Squaring Both Sides, We get

or, 10=2(x-1)

or, 10=2x-2

or, 10+2=2x

or, 12/2 = x

or, 6 = x

Therefore, x = 6

hence, The value of X is 6 Ans..