Math, asked by Gargikshirsagar, 10 months ago

If the side of an equilateral ∆PQR is 8 cm,then what is the height of triangle?

Answers

Answered by rdsharma07
13

Answer:

ANSWER IS IN THE ATTACHMENT

HOPE IT HELPS!!!

Attachments:
Answered by JeanaShupp
8

The height of triangle is 4\sqrt{3}\text{ cm .}

Explanation:

The area of equilateral triangle = \dfrac{\sqrt{3}}{4}(side)^2

If the side of an equilateral ∆PQR is 8 cm , then area of ∆PQR = \dfrac{\sqrt{3}}{4}(8)^2=\dfrac{\sqrt{3}}{4}(64)=16\sqrt{3}\text{ cm}  (1)

Also, area of triangle = (0.5) x (base) x (height) =(0.5)(8)(height)= (4)(height)         (2)

From (1) and (2) ,  we have

(4)(height)   =  16\sqrt{3}\\\\\Rightarrow\ height=4\sqrt{3}

Hence, the height of triangle is 4\sqrt{3}\text{ cm .}

# Learn more :

https://brainly.in/question/12207171

The base of an isosceles isosceles triangle is half that two equal sides the perimeter of triangle is 30 cm what is length of each side of the triangle

Similar questions