Question

if the side of an equilateral triangle is 5 cm what is its area take root 3 =1.732​

Answer 1

Answer:

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Answer 2

Given :

• Length of side of an equilateral triangle = 5 cm

• √3 = 1.732

To find :

• Area of the equilateral triangle

Formula used :

$A = \dfrac{ \sqrt{3} }{4} {a}^{2}$

Where :-

• A = area of equilateral triangle
• a = Length of side of an equilateral triangle

Solution :

Length of side of an equilateral triangle = 5 cm

To find area of the equilateral triangle we will use the following formula :-

$\implies \: A = \dfrac{ \sqrt{3} }{4} {a}^{2}$

Now put :-

• a = 5 cm

• √3 = 1.732

$\implies \: A = \dfrac{1.732 }{4} {(5)}^{2}$

$\implies \: A = \dfrac{1.732 }{4} \times 5 \times 5$

$\implies \: A = \dfrac{1732 }{4} \times 5 \times 5 \times \dfrac{1}{1000}$

$\implies \: A = \dfrac{433 }{1} \times 5 \times 5 \times \dfrac{1}{1000}$

$\implies \: A = \dfrac{433 }{1} \times 25\times \dfrac{1}{1000}$

$\implies \: A = 10825 \times \dfrac{1}{1000}$

$\implies \: A = 10.825 {cm}^{2}$

Answer :

Area of the equilateral triangle = 10.825 cm²

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$\large\bf\blue{Additional-Information}$

Area of circle = πr²

Circumference of circle = 2πr

Area of square = (side)²

perimeter of square = 4× side

area of Rhombus = 1/2(diagonal 1)(diagonal 2)

Area of rectangle = length × breadth

Perimeter of rectangle = 2( length + breadth)

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