Question

if the side of cube is increased by 5%,then the surface area of cube is increased by

Answer 1

Answer:

Let the original side be a then

Original surface area S=6a2

When side is increased by 50%, side becomes 23a then 

Surface area  s=227a2

Hence,

Surface area is increases by x=6a2227a2−6a2×100=125%

This is the required solution.