Physics, asked by mugdhabansal141421, 9 months ago

if the side of the cube is increasing with respect to time at the rate of 3 cm /s , then the volume of cube increses with respect to time when its side is 2 cm is

Answers

Answered by Anonymous
0

Answer:

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Answered by kate4mear
1

Answer:

The answer is 36cm³/s

Explanation: let x be tha side of the cube and v would be the volume.

                      given that the side of the cube is increasing  at the rate of

                       3cm/s. Thus dx/dt =3xcm/s

                       Calculating dv/dt when x=2

                        V =x³ which is the volume of the cube

                        differentiate W.r.t time

                        dv/dt =d(x)³/dt x dx/dt

                        dv/dt =d(x)³/dx x dx/dt

                        dv/dt =x³ x dx/dt

                        dv/dt =3x² x 3

                        dv/dt =9x²

                        When x=2

                         dv/dt→ x=2    =9(2)²

                                               =36

                        Since the value is in cm and time is in secs

                         dv/dt =36cm³/sec

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