Question

if the side of the square be increased by 50%.find the percent increased in area. ​

Answer 1

Answer:

125%

Step-by-step explanation:

Area =$side^{2}$

Area is dependent on side square

Then any change in side will change area squarely

side increase by 50%

Area will be=[side+1/2side]²=

side+1/2side==3/2side

area=[3/2side]²==9/4side²

Percentage increase=

Final-Initial/Initial*100

9/4side²-side²*100=5/4*100=5*25=125

Lets ex:

side=4   area=16

Side increase by 50%

side=6 area=36

Percentage increase===

36-16/16*100=20/16*100=125%

Hope you will like the answer.

All the solution is given .Too much efforts are done

If you are satisfied with the answer then you can mark me brainliest.