Question

If the side of the square increases by 40%, then the area of the square increases by

Answer 1

Let the side of the square be a.

Given that side of the square increases by 40% = a + 40/100 * a

                                                                                = a + 0.4 * a

                                                                                = 1.4a.

We know that Area = a^2

                                 = (1.4)^2

                                 = 1.96a^2.

% increase = (1.96a^2 - a^2)/a^2 * 100

                   = 0.96 * 100

                   = 96.

Answer 2

Given:

The sides of the square is increased by 40%.

Solve:

Let "a" represent the side of the square.

Area of Square= a*a= a²

Given that the square's side grows by 40 percent.

the new side becomes:

= a + 40/100 * a

= a + 0.4 * a

= a+ 0.4a

=1.4a

New side= 1.4a.

Calculating the area of new side=

1.4a * 1.4a

= 1.96a².

Now,

% increase = (1.96a² -a²)/a² * 100

= 0.96 * 100

= 96%

Hence, If the side of the square increases by 40%, then the area of the square increases by 96%

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