Question

If the side of the square is increased by 50 percent, find the percent in area. ​

Answer 1

Answer:

If the side of the square is increased by 50 percent, then 125%  in the area. ​

Step-by-step explanation:

Let side of square =x

Area $= Side^2 = x^2$

After 50% increase in side

side length =x+50% of x $=3/2 x$

Area$=( \frac{3x}{2})^2 = \frac{9}{4}x^2$

percentage increase in are =

$= \frac{A final -A initial}{ A initial} \times 100\\=\frac{\frac{9}{4}x^2 -x^2}{x^2} \times 100\\ = \frac{5x^2}{4x^2} \times 100$

= 125%

​ So, If the side of the square is increased by 50 percent, then 125%  in the area. ​