If the side of triangle are in a.p the perimeter is 30cm the difference between the longest and the shortest side is 4cm. Find all sides of triangle
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a+(a+d) +(a+2d) =30=>a+d=10
a+2d-a=4=>d=2
so, a=8
a+d=10
a+2d=12
a+2d-a=4=>d=2
so, a=8
a+d=10
a+2d=12
Answered by
0
shortest side =x
longest side=x+4
third side=y
x+x+4+y=30
2x+y=26-------------(1)
(x+4)-x=y-(x+4)
----(common diff)
4= y-x+4
y-x=0. or x-y=0---------(2)
solving (1)&(2)
3x=26
x=26/3
longest side=x+4
third side=y
x+x+4+y=30
2x+y=26-------------(1)
(x+4)-x=y-(x+4)
----(common diff)
4= y-x+4
y-x=0. or x-y=0---------(2)
solving (1)&(2)
3x=26
x=26/3
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