Math, asked by noorsharma101018, 5 months ago

if the sides in metre of a triangle measures 72, 75 and 21 what is the measure of its inradius​

Answers

Answered by shagunjoshi52184
1

Step-by-step explanation:

We know that, 75,72 and 21 are Pythagorean triplets

i.e., 75

2

=72

2

+21

2

Length of Hypotenuse =75

Lengths of other sides is 72 and 21

We have the formula for a right angled triangle,

inradius =

2

Sum of Perpendicular Sides− Hypotenuse

inradius =

2

(72+21)− 75

inradius =

2

93− 75

inradius =

2

18

inradius=9

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