if the sides in metre of a triangle measures 72, 75 and 21 what is the measure of its inradius
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Step-by-step explanation:
We know that, 75,72 and 21 are Pythagorean triplets
i.e., 75
2
=72
2
+21
2
Length of Hypotenuse =75
Lengths of other sides is 72 and 21
We have the formula for a right angled triangle,
inradius =
2
Sum of Perpendicular Sides− Hypotenuse
inradius =
2
(72+21)− 75
inradius =
2
93− 75
inradius =
2
18
☺☺☺☺☺☺
inradius=9
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