if the sides of a quadrilateral touch a circle group that the sum of pair of opposite sides is equal to the sum of the Other pair
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now
length of tangent drawn from external point to circle are equal.
AP=AS --> 1
BP=BQ --> 2
CR=CQ --> 3
DR=DS -->4
compare 1, 2, 3 and 4
AP + BP + CR + DR = AS + BQ + CQ +DS
AP + BP + CR + DR = AS + DS + BQ + CQ
AB + CD = AD + BC
hence proved.
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