Question

If the sides of a quadrilateral touch a circle prove that the sum of the pair of opposite side is equal to sum of the other

Answer 1

Answer:

Step-by-step explanation:

It can be observed that

DR = DS (Tangents on the circle from point D) …........... (1)

CR = CQ (Tangents on the circle from point C) …........… (2)

BP = BQ (Tangents on the circle from point B) …........… (3)

AP = AS (Tangents on the circle from point A) …............(4)

Adding all these equations, we obtain

DR + CR + BP + AP = DS + CQ + BQ + AS

(DR + CR) + (BP + AP) = (DS + AS) + (CQ + BQ)

CD + AB = AD + BC  

Answer 2

Answer:

Step-by-step explanation:please mark me brainlist