if the sides of a rhombus are 5 cm each and one diagonal is 8 cm, calculate
(1) the length of the other diagonal, and (ii) the area of the rhombus.
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Diagonals bisect each other and they are perpendicular in rhombus
Let half the length of second diagonal be x
As two diagonals and a side form right angled triangle ;
⇒xsquare +4square= 5 square
=>x= 3
=> length of second side = 2x = 6 cm
area of rhombus =1/2 d1 d2
= 1/2 × 8 ×6
= 24cm square
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