Question

if the sides of a right angle triangle are x, x+2,x+4 (where x > 0),then the value of x is​

Answer 1

Answer:

acc to pytha thm

(x+4)²= x² + (x+2)²

x²+16+8x=x²+x²+4+4x

16+8x=x²+4+4x

x²-4x-12=0

x²+2x-6x-12=0

x(x+2)-6(x+2)=0

(x-6)(x+2)=0

x-6=0 and x+2=0

x=6     (as x>0)

Step-by-step explanation:

Answer 2

Answer:

X=6

Step-by-step explanation:

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