Question

If the sides of a right-angled triangle are of the length x, x + 1 and x – 7, then x = ​

Answer 1

Answer:

it is right answer

Answer 2

There are three sides of length x, x+1, x-7

x+1 is the greatest, which shows it is hypotenuse.

By Pythagorean theorem

$x^2+(x-7)^2=(x+1)^2$

$x^2+(x^2-14x+49)=(x^2+2x+1)$

$2x^2-14x+49-(x^2+2x+1)=(x^2+2x+1)-(x^2+2x+1)$

$x^2-16x+48=0$ is a quadratic equation for x

$x^2-4x-12x+12\times 4=0$

$(x-12)(x-4)=0$

→x=12 or x=4

x is necessary greater than 7, for x-7 to be positive length.

→x=12

Hope it helps bro.