Question

If the sides of a triangle are 20cm, 40cm and 60m respectively then find the area of a triangle by the heron's formula?

Answer 1

Answer:

Correct option is

C

1344cm

2

s=

2

a+b+c

By Heron's formula,Area of the triangle=

s(s−a)(s−b)(s−c)

Where a,b,c are sides of the triangle.

s=

2

56+60+52

=84

Area of the triangle=

84(84−56)(84−60)(84−52)

=

1806336

=1344cm

2

Answer 2

$\bf\pink{QuestioN:-}$

If the sides of a triangle are 20cm, 40cm and 60cm respectively then find the area of a triangle by the heron's formula?

$\bf\blue{AnsweR:-}$

GiveN:-

Sides of the triangular fields are 20 cm , 40 cm and 60 cm.

FormulA  ApplieD:-

Using Heron's formula,

Area of the Triangle = √s(s - a)(s -b)(s - c)

SolutioN:-

In this formula,

'S' here means the semiperimeter.

Perimeter = ( 20 + 40 + 60 ) cm = 120 cm

Then semiperimeter,

         $\bf{S=\dfrac{120}{2}=60\:\:cm}$

Now we can apply the formula here,  

ie, area of the triangle =  √s(s - a)(s -b)(s - c)

$\bf\red{\implies\sqrt{60(60-20)(60-40)(60-60)}}$

$\bf\red{\implies\sqrt{60(40)(20)(0)}}$

When we multipled 0 by a number the answer will always be 0. According to this question root of zero will be the answer. But the area of a triangle is not possible in that measure.

SimilaR QuestioN:-

https://brainly.in/question/34790371

Hope you understand the concept used here!

Happy Learning!! ❤