Question

If the sides of a triangle are 26cm, 24cm and 10cm. what is its area ?​

Answer 1

Step-by-step explanation:

A=s(s﹣a)(s﹣b)(s﹣c)

s=a+b+c

2

Solving forA

A=1

4﹣a4+2(ab)2+2(ac)2﹣b4+2(bc)2﹣c4=1

4·﹣264+2·(26·24)2+2·(26·10)2﹣244+2·(24·10)2﹣104=120cm²

Answer 2

Area =

$\sqrt[ ]{s(s - a)(s - b)(s - c}$

S = 26+24+10/2

= 60/2 = 30 cm

Area you can calculate your self by putting values in formula