Question

If the sides of a triangle are a (3a+2), 5a-8, and 11a^2+7, what is the perimeter

Answer 1

Answer:

Step-by-step explanation:

perimeter of a triangle=sum of all sides

perimeter=(3a+2+5a-8+$11a^{2}$+7)

perimeter=($11a^{2}$+8a-1)