if the sides of a triangle are b-3a+2c, a +3b-3c and 2a-b+c then finds its perimeter
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P =sum of all sides
b-3a+2c+a+3b-3c+2a-b+c
3a+2a+a+3b+b-b+2c+c-3c
=6a +3b-0
6a+3b
It is the answer
Please mark as brainliest
b-3a+2c+a+3b-3c+2a-b+c
3a+2a+a+3b+b-b+2c+c-3c
=6a +3b-0
6a+3b
It is the answer
Please mark as brainliest
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