Question

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If the sides of a triangle are in AP. The perimeter of the triangle is 30 cm. The difference
between the longer and shorter side is 4 cm. Then find all sides of the triangle.​

Answer 1

Answer:

sides are 8,10,12

Step-by-step explanation:

a=10 & d = 2

Answer 2

Answer:

8 10 12

Step-by-step explanation:

let the sides of a triangle be a b c

they are in form of AP so

required AP is a, a+d, A+2d

perimeter of a triangle is 30

a+b+c=30

so a+a+d+a+2d=30

3a+3d=30

3(a+d)=30 {taking out 3 common}

a+d=30

one of its side is 30

the difference between the largest and smallest side is 4

so (a+2d)-(a) = 4

a+2d-a=4

2d=4

d=2

common difference is two

so the required sides are

8 10 12