Math, asked by shreyapathak17112002, 3 months ago

if the sides of a triangle are in the ratio 2:3:5 and the perimeter is 150 find the measure of each side​

Answers

Answered by INigamaI
0

Answer

LET THE FIRST SIDE=2X=A

LET THE SECOND SIDE=3X=B

LET THE THIRD SIDE=5X=C

PERIMETER OF TRIANGLE=150

A+B+C=150

2X+3X+5X=150

10X=150

X=150/10=15

THEREFORE,

A=FIRST SIDE=2X=2(15)=30

B=SECOND SIDE=3X=3(15)=45

C=THIRD SIDE=5X=5(15)=75

HOPE IT HELPS YOU

THANK YOU

Step-by-step explanation:


INigamaI: hi shreya
INigamaI: the perimete of triangle is always 180
INigamaI: ok????
chinni7594: it os sum of all angles in a triangle
INigamaI: I HAVE CHANGED IT
INigamaI: thanks for informing
Answered by chinni7594
1

Step-by-step explanation:

perimeter = sum of all sides

given,

perimeter = 150

sides are the ration of 2:3:5

perimeter of teiangle=

2x+3x+4x=150

10x = 150

x=150/10

x = 15

2x = 2×15

=30

3x= 3×15

=45

5x = 5× 15

=75

the sides are 30,45,75

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