If the sides of a triangle are produced in order, Prove that the sum of the exterior angles so formed is 360°.
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Answered by
599
Suppose you have a ∆ABC
All the exterior angles will be equal to
(180-A)°
(180-B)°
(180-C)°
respectively (Angles on the same line) so if you sum it up it will be equal to 540 - (A+ B + C )
And by angle sum property A+B+C = 180°
Therefore Sum = 540 - 180 = 360
All the exterior angles will be equal to
(180-A)°
(180-B)°
(180-C)°
respectively (Angles on the same line) so if you sum it up it will be equal to 540 - (A+ B + C )
And by angle sum property A+B+C = 180°
Therefore Sum = 540 - 180 = 360
Answered by
151
Answer:
Answer is 360°
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