If the sides of a triangle are produced in order, Prove that the sum of the exterior angles so formed is 360°.
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In ABC , By Angle sum property of triangle,
ABC + BAC + BC A =180°-------(1)
Now, By linear pair property
1 + BAC = 180° ---------(2)
And 2 + ABC = 180° ---------(3)
And 3 + BCA = 180° ---------(4)Add equation (2) (3) and (4)
1 +BAC+2+ABC+3+BCA= 180°+180°+180°
1+2 +3 + BAC+ABC+BCA = 540°
1+2 +3 + 180° = 540° (from eq 1)
1+2 +3 = 540° - 180°
1+2 +3 = 360°
Hence, it is proved that sum exterior angle of triangle is 360°
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