If the sides of a triangles are 13 5 12 find the length of altiyude corresponding to the longest side as base by herons
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Sol:
Sides of the triangle,
a = 20 cm, b = 21 cm, c = 29 cm
S = (a + b + c) / 2
= (20 + 21 + 29) / 2
= 35
Area of the triangle = √[s(s-a)(s-b)(s-c)]
= √[35(35-20)(35-21)(35-29)]
= √[(35)(15)(14)(6)]
= √44100
= 210
So, the area of the triangle is 210 sq cm
Area of the triangle considering the longest side as the base
= 1/2 × base × altitude
1/2 × 29 × altitude = 210
Altitude = (210 x 2) / 29
Altitude = 14.48 cm
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