If the sides of a triangular field are 6800 cm, 8400 cm and
40 m respectively, find the cost of harvesting the field at
the rate of 2.50 per sq m.
(A) 33600
(B) 3360
(C) 3336
(D) 33.60
Answers
According to ur question,
Sides of the triangle are 6800cm,8400cm,40m
Hence,
Sides are 68m , 84m , 40m
semiperimeter = \frac{a + b + c}{2}semiperimeter=2a+b+c
s = \frac{68 + 84 + 40}{2}s=268+84+40
s = \frac{192}{2}s=2192
s = 96ms=96m
Hence, Area if the triangle
area = \sqrt{s(s - a)(s - b)(s - c)}area=s(s−a)(s−b)(s−c)
area = \sqrt{96(96 - 68)(96 - 84)(96 - 40)}area=96(96−68)(96−84)(96−40)
area = \sqrt{96 \times 28 \times 12 \times 56}area=96×28×12×56
area = \sqrt{1806336}area=1806336
area = 1344 {m}^{2}area=1344m2
Hence, Area of triangle is 1344m²
Now,
Total cost of harvesting the field at the rate of Rs 2.5/m²
total \: cost = area \: of \: the \: triangle \times ratetotalcost=areaofthetriangle×rate
total \: cost = 1344 \times 2.5totalcost=1344×2.5
total \: cost \: = 3360rstotalcost=3360rs