Question

if the sides of an equilateral triangle is 6units find the area​

Answer 1

Answer:

$9 \sqrt{3} \: \: uni {t}^{2}$

Step-by-step explanation:

Area of an equilateral triangle is

$\frac{ \sqrt{3} }{4} {a}^{2}$

where a is the sode of the equilateral triangle.

So, as a = 6 unit

Substituting the value of a in the above formula, we get:

Area of triangle =

$\frac{ \sqrt{3} }{4} {6}^{2}$

$= \frac{ \sqrt{3} }{4} \times 6 \times 6$

$= 9 \sqrt{3} \: \: uni {t}^{2}$

Answer 2

Area of equilateral triangle

√3(a)^2/4

√3(6×6)/4

√3 × 36/4

√3 × 9

Area of equilateral triangle of side 6 units is 9√3 unit square

Hope this is helpful