if the sides of areas of two circle is1:16 ,then ratio in their perimeters is
Answers
Answer:
Let the radii of the circles be r
1
& r
2
respectively.
Then, their circumferences are 2πr
1
& 2πr
2
, respectively.
So, their ratio=2πr
1
:2πr
2
=r
1
:r
2
.
Again, the areas of the circles are π(r
1
)
2
& π(r
2
)
2
.
Then, their ratio =π(r
1
)
2
:π(r
2
)
2
=(r
1
)
2
:(r
2
)
2
=16:25 ...(given).
∴(r
1
):(r
2
)=
16:25
=±(4:5)
We reject the negative value of r's since the radius is a length.
∴(r
1
):(r
2
)=(4:5).
Step-by-step explanation:
Answer:
Let the radii of the circles be r1 & r2 respectively.
Then, their circumferences are 2πr1 & 2πr2, respectively.
So, their ratio=2πr1:2πr2=r1:r2.
Again, the areas of the circles are π(r1)2 & π(r2)2.
Then, their ratio =π(r1)2:π(r2)2=(r1)2:(r2)2=16:25 (given).
∴(r1):(r2)=16:25=±(4:5)
We reject the negative value of r's since the radius is a length.
∴(r1):(r2)=(4:5).