if the sides of the field is the ratio 3;4:5 in and its semi perimeter is 72 m. what is the area of the field?
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Step-by-step explanation:
(3x+4x+5x)/2 = 72 => x = 12
(3,4,5) is a triplet of Right angle ∆ so the field will be right triangular in shape.
area = 1/2 * 3x * 4x = 6x = 6(12)
= 72 m^2
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