Question

if the sides of the triangle are 13 cm, 20cm and 21cm find the area. also find the altitude of the triangle corresponding to the largest side​

Answer 1

Answer:

if the sides of the triangle are 13 cm, 20cm and 21cm find the area. also find the altitude of the triangle corresponding to the largest side​

Step-by-step explanation:

if the sides of the triangle are 13 cm, 20cm and 21cm find the area. also find the altitude of the triangle corresponding to the largest side​

Answer 2

Step-by-step explanation:

As given,

=> a = 13 cm

=> b = 20 cm

=> c = 21 cm

Now, We have to find Semi- Perimeter

=> S = a+b+c/2

=> S = 13+20+21/2

=> S = 54/2

=> S = 27

Now, Area of triangle,

$area = \sqrt{s(s - a)(s - b)(s - c)}$

$area = \sqrt{27(27 - 13)(27 - 20)(27 - 21)}$

$area = \sqrt{27 \times 14 \times 7 \times 6}$

$area = \sqrt{3 \times 3 \times 3 \times 7 \times 2 \times 7 \times 2 \times 3}$

$area = 3 \times 3 \times 7 \times 2$

$area = 126cm {}^{2}$

Now, We are required to find out Altitude :-

Here, longest side will 21 cm

Area of Triangle = 1/2 x b x h

=> 126 cm^2 = 1/2 x 20 x h

=> 126 cm^2 = 10 h

=> (126/10) cm = h

=> 12.6 cm

=> h = 12.6

Hope it is Helpful....:)

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