Question

If the sides of triangle are in the ratio 3:7:8 then r:r =

Answer 1

1:1

I hope it is the answer

Answer 2

Given, a=3k,b=7k,c=8k

r = 4Rsin A/2 sin B/2sin C/2

$⇒ \frac{R}{r} = \frac{1}{4sin \frac{A}{2}sin \frac{B}{2}sin \frac{C}{2} }$

$= \frac{1}{ \sqrt{ \frac{(s - b)(s - c)}{bc} \times \frac{(s - a)(s - c)}{ac} \times \frac{(s - a)(s - b)}{ab} } }$

$= \frac{abc}{= </p><p>4(s−a)(s−b)(s−c)} =$

$\frac{(3k)(7k)(8k)}{4(2k)(6k)(k)} = \frac{7}{2}$

∴R:r=7:2