Question

If the sides of triangle is 8 cm ,6 cm, 10

cm , then find the value of (s-a), (s-b),(s-c)​

Answer 1

Answer:

S = A + B + C /2

S = 8 + 6 + 10 /2

S = 24/2 = 12

s-a = 12-8 = 4

s-b = 12-6 = 6

s-c = 12-10 = 2

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Answer 2

Answer:

Step-by-step explanation:

The sides are 6cm,8cm,10cm

$s=\frac{8+6+10}{2}$

$= \frac{24}{2}$

$=12$

The area is given as $\sqrt{s(s-a)(s-b)(s-c)}$

$\sqrt{12(6)(4)(2)}$

$= \sqrt{576}$

$=24 cm^{2}$