if the Simple interest for 2 yeats is Rs 650 and compound interest for 2 years at the same rate and for the same principal is Rs 715, then find the difference between simple interest and compoind interest for 3 years at the same rate and the principal?
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Answer:
The principal is 625 rupee
Rate is 8%
Concept:
SI = (P × R × T)/100
CI = P[(1 + r/100)n - 1]
Here, n is the number of terms in the year.
Calculation:
The simple interest for 2 years
⇒ (625 × 8 × 2)/100
⇒ 25 × 2 × 2
⇒ 100 rupee
Now, Compound interest for 2 years is
⇒ 625[(1 + 8/100)2 - 1]
⇒ 625[(108/100)2 - 1]
⇒ 625[(108)2 - (100)2] × 1/10000
⇒ (208 × 8)/16
⇒ 104 rupee
Now, The difference between CI and SI is
⇒ 104 - 100
⇒ 4
∴ The difference between CI and SI is 4.
The difference between CI and SI for 2 years is P(r/100)2
The difference is
⇒ 625(8/100)2
⇒ 625 × 4/625
⇒ 4
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