If the simple interest on Rs 2000 increases by Rs 40, when the time increases by 4 year. Find the rate per cent per annum.
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14
Answer:
Case 1:
- Principal (P)= Rs2000
- Let rate of interest = R%
- Time = T years
- Simple Interest(l) =Rs x
We know that,
I=PTR/100
x=2000×T×R/100
100x=2000×T×R−−−(1)
Case 2:
- Principal (P)=Rs 2000
- Rate of interest = (R+2)%
- Time = T years
- Simple Interest = Rs (x+40)
x+40=2000×T×(R+2)/100
⟹100(x+40)=2000RT+4000T
⟹100x+4000=2000RT+4000T
100x=2000RT+4000T−4000−−(2)
Now,
From(1)and(2),
we get
2000RT+4000T-4000=2000RT2000RT+4000T−4000=2000RT
⟹4000T=2000RT−2000RT+4000
⟹4000T=4000
⟹T=4000/4000
⟹T=1
Therefore,
Required time (T) = 1 year
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2
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