If the simple interest on Rs.
375 increases by Rs. 75, when
the rate % increases by 5% per
annum. Find the time.
Answers
Answer:
time is 1.25 years.
Step-by-step explanation:
We know that the simple interest on a principal of Rs. P at the rate of r% in a time of n years is given by
S.I.=\dfrac{Prn}{100}.S.I.=
100
Prn
.
So, according to the given information, we have
\begin{gathered}\dfrac{300\times (r+4)\times t}{100}-\dfrac{300\times r\times t}{100}=15\\\\\\\Rightarrow \dfrac{300}{100}\times(rt+4t-rt)=15\\\\\Rightarrow 12t=15\\\\\Rightarrow t=\dfrac{15}{12}\\\\\Rightarrow t=1.25.\end{gathered}
100
300×(r+4)×t
−
100
300×r×t
=15
⇒
100
300
×(rt+4t−rt)=15
⇒12t=15
⇒t=
12
15
⇒t=1.25.
Thus, the required time is 1.25 years.
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Question : If a simple interest on rs. 2000 increases by rs. 40 .when the rate % increases by 2 % per annum find the time?
Step-by-step explanation:
hope you like it!
Answer:
si%=75/375*100 =20%,. one year rate 5% then 20% ,20/5 =4years