If the simultaneous equation 4x-3y=12 and (2p+q) x-(p+q)y =3b have infinitely many solution then what are the values of P and a respectively
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for two lines to have many solutions ...they must be coincident lines...
so on comparing both equations
2p+q/4 = p+q/3 = 3b/12
if b=4 then 2p+q=4 and p+q=3
on solving those two equations
p=1 and q=2
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