If the sin square theta is equal to 1 upon 2 then find out the value of cos square theta ...... Using Pythagoras theorem
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sin²theta = 1/2
sin theta = 1/√2
p/h = 1/√2
p = 1 h = √ 2
b = √ h² - p²
= √1 = 1
cos² theta = 1/(√2)²
= 1/2 ans
abhay5247:
b = √ h² - p²
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